Advertisements
Advertisements
प्रश्न
The square root of 64 divided by the cube root of 64 is
पर्याय
64
2
\[\frac{1}{2}\]
642/3
Advertisements
उत्तर
We have to find the value of `(2sqrt64)/(3sqrt64)`
So,
`(2sqrt64)/(3sqrt64) = (2(sqrt2 xx 2 xx 2 xx 2 xx 2 xx 2) )/(2(sqrt2 xx 2 xx 2 xx 2 xx 2 xx 2) )`
`= 2^(6xx 1/2)`
`= 2^(6xx 1/3)`
`= 2^(6xx 1/2)/2^(6xx 1/3)`
`(2sqrt64)/(3sqrt64) = 2^3/2^2`
`=2^(3-2)`
`=2^1`
= 2
The value of `(2sqrt64)/(3sqrt64)` is 2.
Hence the correct choice is b.
APPEARS IN
संबंधित प्रश्न
Solve the following equations for x:
`2^(2x)-2^(x+3)+2^4=0`
Assuming that x, y, z are positive real numbers, simplify the following:
`root5(243x^10y^5z^10)`
If 3x = 5y = (75)z, show that `z=(xy)/(2x+y)`
State the quotient law of exponents.
The seventh root of x divided by the eighth root of x is
When simplified \[( x^{- 1} + y^{- 1} )^{- 1}\] is equal to
The value of 64-1/3 (641/3-642/3), is
If \[\frac{2^{m + n}}{2^{n - m}} = 16\], \[\frac{3^p}{3^n} = 81\] and \[a = 2^{1/10}\],than \[\frac{a^{2m + n - p}}{( a^{m - 2n + 2p} )^{- 1}} =\]
\[\frac{1}{\sqrt{9} - \sqrt{8}}\] is equal to
Simplify:
`7^(1/2) . 8^(1/2)`
