Advertisements
Advertisements
प्रश्न
Write \[\left( 625 \right)^{- 1/4}\] in decimal form.
Advertisements
उत्तर
We have to write `(625)^(-1/4)`in decimal form. So,
\[\left( 625 \right)^\frac{- 1}{4} = \frac{1}{{625}^\frac{1}{4}}\]
\[ = \left( \frac{1}{\left( 5^4 \right)} \right)^\frac{1}{4}\]
`(625)^(-1/4) = (1 /5)^(4 xx 1/4)`
`=1/5`
= 0.2
Hence the decimal form of `(625)^(-1/4)` is 0.2
APPEARS IN
संबंधित प्रश्न
Solve the following equation for x:
`7^(2x+3)=1`
Show that:
`{(x^(a-a^-1))^(1/(a-1))}^(a/(a+1))=x`
If 2x = 3y = 12z, show that `1/z=1/y+2/x`
Find the value of x in the following:
`2^(5x)div2x=root5(2^20)`
If a, m, n are positive ingegers, then \[\left\{ \sqrt[m]{\sqrt[n]{a}} \right\}^{mn}\] is equal to
If x is a positive real number and x2 = 2, then x3 =
If \[2^{- m} \times \frac{1}{2^m} = \frac{1}{4},\] then \[\frac{1}{14}\left\{ ( 4^m )^{1/2} + \left( \frac{1}{5^m} \right)^{- 1} \right\}\] is equal to
The positive square root of \[7 + \sqrt{48}\] is
If \[\sqrt{13 - a\sqrt{10}} = \sqrt{8} + \sqrt{5}, \text { then a } =\]
Simplify:
`(9^(1/3) xx 27^(-1/2))/(3^(1/6) xx 3^(- 2/3))`
