Advertisements
Advertisements
Question
Write \[\left( 625 \right)^{- 1/4}\] in decimal form.
Advertisements
Solution
We have to write `(625)^(-1/4)`in decimal form. So,
\[\left( 625 \right)^\frac{- 1}{4} = \frac{1}{{625}^\frac{1}{4}}\]
\[ = \left( \frac{1}{\left( 5^4 \right)} \right)^\frac{1}{4}\]
`(625)^(-1/4) = (1 /5)^(4 xx 1/4)`
`=1/5`
= 0.2
Hence the decimal form of `(625)^(-1/4)` is 0.2
APPEARS IN
RELATED QUESTIONS
Simplify the following
`(4ab^2(-5ab^3))/(10a^2b^2)`
Solve the following equations for x:
`3^(2x+4)+1=2.3^(x+2)`
Given `4725=3^a5^b7^c,` find
(i) the integral values of a, b and c
(ii) the value of `2^-a3^b7^c`
If `a=xy^(p-1), b=xy^(q-1)` and `c=xy^(r-1),` prove that `a^(q-r)b^(r-p)c^(p-q)=1`
Prove that:
`sqrt(1/4)+(0.01)^(-1/2)-(27)^(2/3)=3/2`
If `27^x=9/3^x,` find x.
If `3^(x+1)=9^(x-2),` find the value of `2^(1+x)`
Show that:
`((a+1/b)^mxx(a-1/b)^n)/((b+1/a)^mxx(b-1/a)^n)=(a/b)^(m+n)`
The seventh root of x divided by the eighth root of x is
If \[\sqrt{2} = 1 . 4142\] then \[\sqrt{\frac{\sqrt{2} - 1}{\sqrt{2} + 1}}\] is equal to
