Advertisements
Advertisements
Question
Simplify the following
`((x^2y^2)/(a^2b^3))^n`
Advertisements
Solution
`((x^2y^2)/(a^2b^3))^n`
`=((x^2)^n(y^2)^n)/((a^2)^n(b^3)^n)`
`=(x^(2n)y^(2n))/(a^(2n)b^(3n))`
APPEARS IN
RELATED QUESTIONS
Simplify the following:
`(3^nxx9^(n+1))/(3^(n-1)xx9^(n-1))`
Simplify the following:
`(5xx25^(n+1)-25xx5^(2n))/(5xx5^(2n+3)-25^(n+1))`
Prove that:
`(2^(1/2)xx3^(1/3)xx4^(1/4))/(10^(-1/5)xx5^(3/5))div(3^(4/3)xx5^(-7/5))/(4^(-3/5)xx6)=10`
If 3x = 5y = (75)z, show that `z=(xy)/(2x+y)`
If `5^(3x)=125` and `10^y=0.001,` find x and y.
If a and b are different positive primes such that
`((a^-1b^2)/(a^2b^-4))^7div((a^3b^-5)/(a^-2b^3))=a^xb^y,` find x and y.
If `a=x^(m+n)y^l, b=x^(n+l)y^m` and `c=x^(l+m)y^n,` Prove that `a^(m-n)b^(n-l)c^(l-m)=1`
State the product law of exponents.
If a, m, n are positive ingegers, then \[\left\{ \sqrt[m]{\sqrt[n]{a}} \right\}^{mn}\] is equal to
\[\frac{5^{n + 2} - 6 \times 5^{n + 1}}{13 \times 5^n - 2 \times 5^{n + 1}}\] is equal to
