Advertisements
Advertisements
Question
Find the value of x in the following:
`(13)^(sqrtx)=4^4-3^4-6`
Advertisements
Solution
Given `(13)^(sqrtx)=4^4-3^4-6`
`(13)^(sqrtx)=(2^2)^4-3^4-6`
`rArr(13)^(sqrtx)=2^8-3^4-6`
`rArr(13)^sqrtx=256-81-6`
`rArr(13)^sqrtx=169`
`rArr(13)^sqrtx=(13)^2`
On comparing we get,
`sqrtx=2`
On squaring both side we get,
x = 4
Hence, the value of x = 4.
APPEARS IN
RELATED QUESTIONS
Find:-
`9^(3/2)`
Prove that:
`1/(1 + x^(b - a) + x^(c - a)) + 1/(1 + x^(a - b) + x^(c - b)) + 1/(1 + x^(b - c) + x^(a - c)) = 1`
If `27^x=9/3^x,` find x.
If `5^(3x)=125` and `10^y=0.001,` find x and y.
Write the value of \[\left\{ 5( 8^{1/3} + {27}^{1/3} )^3 \right\}^{1/4} . \]
The square root of 64 divided by the cube root of 64 is
When simplified \[(256) {}^{- ( 4^{- 3/2} )}\] is
The positive square root of \[7 + \sqrt{48}\] is
Find:-
`32^(1/5)`
Find:-
`125^((-1)/3)`
