Advertisements
Advertisements
Question
Assuming that x, y, z are positive real numbers, simplify the following:
`(sqrt(x^-3))^5`
Advertisements
Solution
We have to simplify the following, assuming that x, y, z are positive real numbers
Given `(sqrt(x^-3))^5`
As x is positive real number then we have
`(sqrt(x^-3))^5=(sqrt(1/x^3))^5`
`=(sqrt1/sqrt(x^3))^5`
`=(1/x^(3xx1/2))^5`
`=(1/x^(3/2))`
`(sqrt(x^-3))^5=(1^5/x^(3/2xx5))`
`=1/x^(15/2)`
Hence the simplified value of `(sqrt(x^-3))^5` is `1/x^(15/2)`
APPEARS IN
RELATED QUESTIONS
Simplify the following
`(a^(3n-9))^6/(a^(2n-4))`
Solve the following equations for x:
`3^(2x+4)+1=2.3^(x+2)`
Prove that:
`((0.6)^0-(0.1)^-1)/((3/8)^-1(3/2)^3+((-1)/3)^-1)=(-3)/2`
If 3x = 5y = (75)z, show that `z=(xy)/(2x+y)`
If `3^(x+1)=9^(x-2),` find the value of `2^(1+x)`
Simplify:
`(x^(a+b)/x^c)^(a-b)(x^(b+c)/x^a)^(b-c)(x^(c+a)/x^b)^(c-a)`
If (x − 1)3 = 8, What is the value of (x + 1)2 ?
If \[\frac{x}{x^{1 . 5}} = 8 x^{- 1}\] and x > 0, then x =
If \[4x - 4 x^{- 1} = 24,\] then (2x)x equals
If \[2^{- m} \times \frac{1}{2^m} = \frac{1}{4},\] then \[\frac{1}{14}\left\{ ( 4^m )^{1/2} + \left( \frac{1}{5^m} \right)^{- 1} \right\}\] is equal to
