Advertisements
Advertisements
Question
Simplify:
`root3((343)^-2)`
Advertisements
Solution
Given `root3((343)^-2)`
`root3((343)^-2)=root3(1/343^2)`
`=root3(1/(7^3)^2)`
`=1^(1/3)/7^(3xx1/3xx2)`
`=1/7^2`
`=1/49`
Hence the value of `root3((343)^-2)` is `1/49`
APPEARS IN
RELATED QUESTIONS
Simplify:-
`2^(2/3). 2^(1/5)`
Prove that:
`(x^a/x^b)^(a^2+ab+b^2)xx(x^b/x^c)^(b^2+bc+c^2)xx(x^c/x^a)^(c^2+ca+a^2)=1`
Prove that:
`(a+b+c)/(a^-1b^-1+b^-1c^-1+c^-1a^-1)=abc`
Show that:
`(x^(a-b))^(a+b)(x^(b-c))^(b+c)(x^(c-a))^(c+a)=1`
Find the value of x in the following:
`(2^3)^4=(2^2)^x`
Solve the following equation:
`4^(2x)=(root3 16)^(-6/y)=(sqrt8)^2`
Write \[\left( \frac{1}{9} \right)^{- 1/2} \times (64 )^{- 1/3}\] as a rational number.
If o <y <x, which statement must be true?
If \[x = 7 + 4\sqrt{3}\] and xy =1, then \[\frac{1}{x^2} + \frac{1}{y^2} =\]
If \[x + \sqrt{15} = 4,\] then \[x + \frac{1}{x}\] =
