Advertisements
Advertisements
Question
If `1176=2^a3^b7^c,` find a, b and c.
Advertisements
Solution
First find out the prime factorisation of 1176.
It can be observed that 1176 can be written as `2^3xx3^1xx7^2.`
`1176=2^3 3^1 7^2 = 2^a3^b7^c`
Hence, a = 3, b = 1 and c = 2.
shaalaa.com
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Find:-
`9^(3/2)`
If a = 3 and b = -2, find the values of :
(a + b)ab
Prove that:
`(a+b+c)/(a^-1b^-1+b^-1c^-1+c^-1a^-1)=abc`
Simplify:
`root5((32)^-3)`
Show that:
`(3^a/3^b)^(a+b)(3^b/3^c)^(b+c)(3^c/3^a)^(c+a)=1`
If a, b, c are positive real numbers, then \[\sqrt{a^{- 1} b} \times \sqrt{b^{- 1} c} \times \sqrt{c^{- 1} a}\] is equal to
If 102y = 25, then 10-y equals
If \[\sqrt{13 - a\sqrt{10}} = \sqrt{8} + \sqrt{5}, \text { then a } =\]
Find:-
`32^(1/5)`
Which of the following is equal to x?
