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Question
If `1176=2^a3^b7^c,` find a, b and c.
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Solution
First find out the prime factorisation of 1176.
It can be observed that 1176 can be written as `2^3xx3^1xx7^2.`
`1176=2^3 3^1 7^2 = 2^a3^b7^c`
Hence, a = 3, b = 1 and c = 2.
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