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Question
If g = `t^(2/3) + 4t^(-1/2)`, what is the value of g when t = 64?
Options
`31/2`
`33/2`
16
`257/16`
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Solution
`bb(33/2)`
Explanation:
g = `t^(2/3) + 4t^(-1/2)`
= `(64)^(2/3) + 4(64)^(-1/2)`
= `[(64)^(1/3)]^3 + 4 (1/64)^(1/2)`
= `4^2 + 4(1/8)`
= `16 + 1/2 = 38/2`
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