Advertisements
Advertisements
Question
If 24 × 42 =16x, then find the value of x.
Advertisements
Solution
We have to find the value of x provided `2 ^4xx 4^2 = 16^x`
So,
`2 ^4xx 4^2 = 16^x`
`2 ^4xx 2^4 = 2^(4_x)`
`2 ^(4+4) = 2^(4_x)`
By equating the exponents we get
4 + 4 + = 4x
8 = 4x
`8/4 = x `
2=x
Hence the value of x is 2 .
APPEARS IN
RELATED QUESTIONS
Prove that:
`(a^-1+b^-1)^-1=(ab)/(a+b)`
Simplify the following:
`(6(8)^(n+1)+16(2)^(3n-2))/(10(2)^(3n+1)-7(8)^n)`
Assuming that x, y, z are positive real numbers, simplify the following:
`(x^((-2)/3)y^((-1)/2))^2`
Assuming that x, y, z are positive real numbers, simplify the following:
`root5(243x^10y^5z^10)`
Find the value of x in the following:
`5^(2x+3)=1`
If `3^(x+1)=9^(x-2),` find the value of `2^(1+x)`
Simplify:
`root(lm)(x^l/x^m)xxroot(mn)(x^m/x^n)xxroot(nl)(x^n/x^l)`
The product of the square root of x with the cube root of x is
\[\frac{5^{n + 2} - 6 \times 5^{n + 1}}{13 \times 5^n - 2 \times 5^{n + 1}}\] is equal to
The positive square root of \[7 + \sqrt{48}\] is
