Question

If \[8^{x + 1}\] = 64 , what is the value of \[3^{2x + 1}\] ?

Options

• 1

• 3

• 9

• 27

Answer 1

We have to find the value of  `3^2x+1` provided `8^((x+1) = 64)`

So,

 `2^(3(x+1)) = 64`

`2^(3x+3) = 2^6`

Equating the exponents we get

`3x + 3= 6 `

`3x= 6-3`

`3x=3`

`x= 3/3`

 x - 1

By substitute in  `3^(2x+1)`we get 

`3^(2 xx 1 +1)`

` = 3^(2+1)`

`= 3^3`

`= 27`

The real value of `3^(2x+1)` is 27