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प्रश्न
If \[8^{x + 1}\] = 64 , what is the value of \[3^{2x + 1}\] ?
पर्याय
1
3
9
27
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उत्तर
We have to find the value of `3^2x+1` provided `8^((x+1) = 64)`
So,
`2^(3(x+1)) = 64`
`2^(3x+3) = 2^6`
Equating the exponents we get
`3x + 3= 6 `
`3x= 6-3`
`3x=3`
`x= 3/3`
x - 1
By substitute in `3^(2x+1)`we get
`3^(2 xx 1 +1)`
` = 3^(2+1)`
`= 3^3`
`= 27`
The real value of `3^(2x+1)` is 27
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