Advertisements
Advertisements
प्रश्न
If (23)2 = 4x, then 3x =
पर्याय
3
6
9
27
Advertisements
उत्तर
We have to find the value of `3^x`provided `(2^3)^2 = 4`
So,
`2^(3xx 2) = 2^(2x)`
`2^6 = 2^(2x)`
By equating the exponents we get
`6=2x`
`6/2 = x`
`3=x`
By substituting in `3^x`we get
`3^x = 3^3`
`=27`
The value of`3^x` is 27
APPEARS IN
संबंधित प्रश्न
Simplify the following
`(a^(3n-9))^6/(a^(2n-4))`
Simplify the following:
`(6(8)^(n+1)+16(2)^(3n-2))/(10(2)^(3n+1)-7(8)^n)`
Prove that:
`(2^n+2^(n-1))/(2^(n+1)-2^n)=3/2`
Simplify:
`(x^(a+b)/x^c)^(a-b)(x^(b+c)/x^a)^(b-c)(x^(c+a)/x^b)^(c-a)`
If 3x-1 = 9 and 4y+2 = 64, what is the value of \[\frac{x}{y}\] ?
When simplified \[\left( - \frac{1}{27} \right)^{- 2/3}\] is
If 10x = 64, what is the value of \[{10}^\frac{x}{2} + 1 ?\]
If \[x = \frac{\sqrt{5} + \sqrt{3}}{\sqrt{5} - \sqrt{3}}\] and \[y = \frac{\sqrt{5} - \sqrt{3}}{\sqrt{5} + \sqrt{3}}\] then x + y +xy=
Find:-
`16^(3/4)`
Simplify:
`(9^(1/3) xx 27^(-1/2))/(3^(1/6) xx 3^(- 2/3))`
