Advertisements
Advertisements
प्रश्न
Find the value of x in the following:
`(13)^(sqrtx)=4^4-3^4-6`
Advertisements
उत्तर
Given `(13)^(sqrtx)=4^4-3^4-6`
`(13)^(sqrtx)=(2^2)^4-3^4-6`
`rArr(13)^(sqrtx)=2^8-3^4-6`
`rArr(13)^sqrtx=256-81-6`
`rArr(13)^sqrtx=169`
`rArr(13)^sqrtx=(13)^2`
On comparing we get,
`sqrtx=2`
On squaring both side we get,
x = 4
Hence, the value of x = 4.
APPEARS IN
संबंधित प्रश्न
Simplify the following
`3(a^4b^3)^10xx5(a^2b^2)^3`
If a = 3 and b = -2, find the values of :
(a + b)ab
Prove that:
`(a^-1+b^-1)^-1=(ab)/(a+b)`
Prove that:
`((0.6)^0-(0.1)^-1)/((3/8)^-1(3/2)^3+((-1)/3)^-1)=(-3)/2`
Find the value of x in the following:
`2^(x-7)xx5^(x-4)=1250`
Solve the following equation:
`4^(2x)=(root3 16)^(-6/y)=(sqrt8)^2`
If x is a positive real number and x2 = 2, then x3 =
If 10x = 64, what is the value of \[{10}^\frac{x}{2} + 1 ?\]
If x= \[\frac{\sqrt{3} - \sqrt{2}}{\sqrt{3} + \sqrt{2}}\] and y = \[\frac{\sqrt{3} + \sqrt{2}}{\sqrt{3} - \sqrt{2}}\] , then x2 + y +y2 =
Find:-
`16^(3/4)`
