Advertisements
Advertisements
प्रश्न
Find the value of x in the following:
`(13)^(sqrtx)=4^4-3^4-6`
Advertisements
उत्तर
Given `(13)^(sqrtx)=4^4-3^4-6`
`(13)^(sqrtx)=(2^2)^4-3^4-6`
`rArr(13)^(sqrtx)=2^8-3^4-6`
`rArr(13)^sqrtx=256-81-6`
`rArr(13)^sqrtx=169`
`rArr(13)^sqrtx=(13)^2`
On comparing we get,
`sqrtx=2`
On squaring both side we get,
x = 4
Hence, the value of x = 4.
APPEARS IN
संबंधित प्रश्न
Assuming that x, y, z are positive real numbers, simplify the following:
`(x^-4/y^-10)^(5/4)`
Show that:
`{(x^(a-a^-1))^(1/(a-1))}^(a/(a+1))=x`
Show that:
`(3^a/3^b)^(a+b)(3^b/3^c)^(b+c)(3^c/3^a)^(c+a)=1`
If `x=2^(1/3)+2^(2/3),` Show that x3 - 6x = 6
If `2^x xx3^yxx5^z=2160,` find x, y and z. Hence, compute the value of `3^x xx2^-yxx5^-z.`
If `x = a^(m + n), y = a^(n + l)` and `z = a^(l + m),` prove that `x^my^nz^l = x^ny^lz^m`
If 9x+2 = 240 + 9x, then x =
The value of 64-1/3 (641/3-642/3), is
If x = \[\frac{2}{3 + \sqrt{7}}\],then (x−3)2 =
Simplify:
`(3/5)^4 (8/5)^-12 (32/5)^6`
