Advertisements
Advertisements
प्रश्न
Find the value of x in the following:
`(sqrt(3/5))^(x+1)=125/27`
Advertisements
उत्तर
Given `(sqrt(3/5))^(x+1)=125/27`
`(sqrt(3/5))^(x+1)=(5/3)^3`
`rArr(3/5)^((x+1)/2)=(3/5)^-3`
On comparing we get,
`(x+1)/2=-3`
⇒ x + 1 = -3 x 2
⇒ x + 1 = -6
⇒ x = -6 - 1
⇒ x = -7
Hence, the value of x = -7.
APPEARS IN
संबंधित प्रश्न
If a = 3 and b = -2, find the values of :
ab + ba
Prove that:
`9^(3/2)-3xx5^0-(1/81)^(-1/2)=15`
Prove that:
`(64/125)^(-2/3)+1/(256/625)^(1/4)+(sqrt25/root3 64)=65/16`
If 2x = 3y = 12z, show that `1/z=1/y+2/x`
Find the value of x in the following:
`(3/5)^x(5/3)^(2x)=125/27`
Find the value of x in the following:
`(root3 4)^(2x+1/2)=1/32`
Which one of the following is not equal to \[\left( \frac{100}{9} \right)^{- 3/2}\]?
`(2/3)^x (3/2)^(2x)=81/16 `then x =
The value of m for which \[\left[ \left\{ \left( \frac{1}{7^2} \right)^{- 2} \right\}^{- 1/3} \right]^{1/4} = 7^m ,\] is
(256)0.16 × (256)0.09
