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प्रश्न
Find:-
`125^(1/3)`
बेरीज
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उत्तर
We can write the given expression as follows
⇒ `125^(1/3) = (5^3)^(1/3)`
On simplifying
⇒ `125^(1/3) = 5^(3 xx 1/3)`
∴ `125^(1/3) = 5`
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पाठ 1: Number Systems - EXERCISE 1.5 [पृष्ठ २३]
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संबंधित प्रश्न
Assuming that x, y, z are positive real numbers, simplify the following:
`sqrt(x^3y^-2)`
Simplify:
`(16^(-1/5))^(5/2)`
Prove that:
`((0.6)^0-(0.1)^-1)/((3/8)^-1(3/2)^3+((-1)/3)^-1)=(-3)/2`
Show that:
`(a^(x+1)/a^(y+1))^(x+y)(a^(y+2)/a^(z+2))^(y+z)(a^(z+3)/a^(x+3))^(z+x)=1`
Find the value of x in the following:
`(2^3)^4=(2^2)^x`
Find the value of x in the following:
`5^(x-2)xx3^(2x-3)=135`
Find the value of x in the following:
`(sqrt(3/5))^(x+1)=125/27`
State the product law of exponents.
If 3x-1 = 9 and 4y+2 = 64, what is the value of \[\frac{x}{y}\] ?
Find:-
`125^((-1)/3)`
