Advertisements
Advertisements
प्रश्न
If a, b, c are positive real numbers, then \[\sqrt{a^{- 1} b} \times \sqrt{b^{- 1} c} \times \sqrt{c^{- 1} a}\] is equal to
पर्याय
1
abc
\[\sqrt{abc}\]
\[\frac{1}{abc}\]
Advertisements
उत्तर
We have to find the value of `sqrt(a^-1b)xx sqrt (b^-1c) xx sqrt(c^-1 a)` when a, b, c are positive real numbers.
So,
`sqrt(a^-1b)xx sqrt (b^-1c) xx sqrt(c^-1 a) =sqrt(1/a xxb)xx sqrt(1/b xx c) xx sqrt(1/c xx a)`
`sqrt(b/a) xx sqrt (c/b) xx sqrt(a/c)`
Taking square root as common we get
\[\sqrt{a^{- 1} b} \times \sqrt{b^{- 1} c} \times \sqrt{c^{- 1} a} = \sqrt{\frac{b}{a} \times \frac{c}{b} \times \frac{a}{c}}\]
\[\sqrt{a^{- 1} b} \times \sqrt{b^{- 1} c} \times \sqrt{c^{- 1} a} = 1\]
APPEARS IN
संबंधित प्रश्न
Prove that:
`(x^a/x^b)^cxx(x^b/x^c)^axx(x^c/x^a)^b=1`
Given `4725=3^a5^b7^c,` find
(i) the integral values of a, b and c
(ii) the value of `2^-a3^b7^c`
Assuming that x, y, z are positive real numbers, simplify the following:
`root5(243x^10y^5z^10)`
Show that:
`(a^(x+1)/a^(y+1))^(x+y)(a^(y+2)/a^(z+2))^(y+z)(a^(z+3)/a^(x+3))^(z+x)=1`
If 2x = 3y = 6-z, show that `1/x+1/y+1/z=0`
Solve the following equation:
`sqrt(a/b)=(b/a)^(1-2x),` where a and b are distinct primes.
Which one of the following is not equal to \[\left( \frac{100}{9} \right)^{- 3/2}\]?
If 9x+2 = 240 + 9x, then x =
If (16)2x+3 =(64)x+3, then 42x-2 =
If x = \[\sqrt[3]{2 + \sqrt{3}}\] , then \[x^3 + \frac{1}{x^3} =\]
