Advertisements
Advertisements
प्रश्न
Assuming that x, y, z are positive real numbers, simplify the following:
`root5(243x^10y^5z^10)`
Advertisements
उत्तर
We have to simplify the following, assuming that x, y, z are positive real numbers
Given `root5(243x^10y^5z^10)`
`=(243xx x^10xxy^5xxz^10)^(1/5)`
`=(243)^(1/5)xx (x^10)^(1/5)xx(y^5)^(1/5)xx(z^10)^(1/5)`
`=(3^5)^(1/5)xx x^(10xx1/5)xxy^(5xx1/5)xxz^(10xx1/5)`
`=3xx x^2xxyxxz^2`
`=3x^2yz^2`
APPEARS IN
संबंधित प्रश्न
Simplify the following:
`(3^nxx9^(n+1))/(3^(n-1)xx9^(n-1))`
Find the value of x in the following:
`(2^3)^4=(2^2)^x`
Find the value of x in the following:
`5^(2x+3)=1`
Simplify:
`(x^(a+b)/x^c)^(a-b)(x^(b+c)/x^a)^(b-c)(x^(c+a)/x^b)^(c-a)`
State the product law of exponents.
If 3x-1 = 9 and 4y+2 = 64, what is the value of \[\frac{x}{y}\] ?
Which one of the following is not equal to \[\left( \sqrt[3]{8} \right)^{- 1/2} ?\]
If \[\frac{x}{x^{1 . 5}} = 8 x^{- 1}\] and x > 0, then x =
If \[x = \frac{\sqrt{5} + \sqrt{3}}{\sqrt{5} - \sqrt{3}}\] and \[y = \frac{\sqrt{5} - \sqrt{3}}{\sqrt{5} + \sqrt{3}}\] then x + y +xy=
Find:-
`125^(1/3)`
