Advertisements
Advertisements
प्रश्न
If `1176=2^a3^b7^c,` find a, b and c.
Advertisements
उत्तर
First find out the prime factorisation of 1176.
It can be observed that 1176 can be written as `2^3xx3^1xx7^2.`
`1176=2^3 3^1 7^2 = 2^a3^b7^c`
Hence, a = 3, b = 1 and c = 2.
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Simplify the following:
`(6(8)^(n+1)+16(2)^(3n-2))/(10(2)^(3n+1)-7(8)^n)`
Solve the following equation for x:
`2^(x+1)=4^(x-3)`
If ax = by = cz and b2 = ac, show that `y=(2zx)/(z+x)`
Simplify:
`(x^(a+b)/x^c)^(a-b)(x^(b+c)/x^a)^(b-c)(x^(c+a)/x^b)^(c-a)`
Write the value of \[\sqrt[3]{125 \times 27}\].
If \[4x - 4 x^{- 1} = 24,\] then (2x)x equals
When simplified \[(256) {}^{- ( 4^{- 3/2} )}\] is
If \[\frac{5 - \sqrt{3}}{2 + \sqrt{3}} = x + y\sqrt{3}\] , then
The value of \[\sqrt{3 - 2\sqrt{2}}\] is
Find:-
`125^((-1)/3)`
