Advertisements
Advertisements
Question
Solve the following equation for x:
`2^(x+1)=4^(x-3)`
Advertisements
Solution
`2^(x+1)=4^(x-3)`
`rArr2^(x+1)=(2^2)^(x-3)`
`rArr2^(x+1)=(2^(2x-6))`
⇒ x + 1 = 2x - 6
⇒ 2x - x = 1 + 6
⇒ x = 7
shaalaa.com
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
If a = 3 and b = -2, find the values of :
aa + bb
Prove that:
`sqrt(1/4)+(0.01)^(-1/2)-(27)^(2/3)=3/2`
Show that:
`(3^a/3^b)^(a+b)(3^b/3^c)^(b+c)(3^c/3^a)^(c+a)=1`
If 2x = 3y = 12z, show that `1/z=1/y+2/x`
Find the value of x in the following:
`(root3 4)^(2x+1/2)=1/32`
Solve the following equation:
`8^(x+1)=16^(y+2)` and, `(1/2)^(3+x)=(1/4)^(3y)`
Show that:
`((a+1/b)^mxx(a-1/b)^n)/((b+1/a)^mxx(b-1/a)^n)=(a/b)^(m+n)`
State the quotient law of exponents.
If 24 × 42 =16x, then find the value of x.
If 102y = 25, then 10-y equals
