Advertisements
Advertisements
Question
(256)0.16 × (256)0.09
Options
4
16
64
256.25
Advertisements
Solution
We have to find the value of `(256)^0.16 xx (256)^0.09`So,
By using law of rational exponents
`a^m xx a^n = a^(m+n)` we get
`(256)^0.16 xx (256)^0.09 = (256)^0.16 xx (256)^0.09`
=`(256)^(0.16+0.09)`
= `256^(0.25)`
=`(256)^(25/100)`
`(256)^0.16 xx (256)^0.09 = 2^(8 xx 25/100)`
= `2^(8 xx 25/100)`
` = 2^(8 xx 1/4)`
` = 2^(8 xx 1/4)`
= 4
The value of `(256)^0.16 xx (256)^0.09 `is 4
APPEARS IN
RELATED QUESTIONS
Simplify:
`(sqrt2/5)^8div(sqrt2/5)^13`
Show that:
`1/(1+x^(a-b))+1/(1+x^(b-a))=1`
If ax = by = cz and b2 = ac, show that `y=(2zx)/(z+x)`
If 3x-1 = 9 and 4y+2 = 64, what is the value of \[\frac{x}{y}\] ?
If \[8^{x + 1}\] = 64 , what is the value of \[3^{2x + 1}\] ?
If x-2 = 64, then x1/3+x0 =
When simplified \[\left( - \frac{1}{27} \right)^{- 2/3}\] is
If \[\sqrt{5^n} = 125\] then `5nsqrt64`=
If \[x = 7 + 4\sqrt{3}\] and xy =1, then \[\frac{1}{x^2} + \frac{1}{y^2} =\]
Which of the following is equal to x?
