Advertisements
Advertisements
प्रश्न
If 1176 = `2^axx3^bxx7^c,` find the values of a, b and c. Hence, compute the value of `2^axx3^bxx7^-c` as a fraction.
Advertisements
उत्तर
First find the prime factorisation of 1176.
It can be observed that 1176 can be written as `2^3xx3^1xx7^2`
`1176=2^a3^b7^c=2^3 3^1 7^2`
So, a = 3, b = 1 and c = 2.
Therefore, the value of `2^a xx3^bxx76-c` is `2^3xx3^1xx7^-2=8xx3xx1/49=24/49`
APPEARS IN
संबंधित प्रश्न
Solve the following equation for x:
`4^(x-1)xx(0.5)^(3-2x)=(1/8)^x`
Assuming that x, y, z are positive real numbers, simplify the following:
`sqrt(x^3y^-2)`
Assuming that x, y, z are positive real numbers, simplify the following:
`(x^-4/y^-10)^(5/4)`
Find the value of x in the following:
`(13)^(sqrtx)=4^4-3^4-6`
Solve the following equation:
`8^(x+1)=16^(y+2)` and, `(1/2)^(3+x)=(1/4)^(3y)`
Solve the following equation:
`sqrt(a/b)=(b/a)^(1-2x),` where a and b are distinct primes.
If `a=x^(m+n)y^l, b=x^(n+l)y^m` and `c=x^(l+m)y^n,` Prove that `a^(m-n)b^(n-l)c^(l-m)=1`
Write the value of \[\sqrt[3]{125 \times 27}\].
If \[8^{x + 1}\] = 64 , what is the value of \[3^{2x + 1}\] ?
Which one of the following is not equal to \[\left( \frac{100}{9} \right)^{- 3/2}\]?
