Advertisements
Advertisements
प्रश्न
Write \[\left( \frac{1}{9} \right)^{- 1/2} \times (64 )^{- 1/3}\] as a rational number.
Advertisements
उत्तर
We have to find the value of . `(1/9) ^((-1)/2) xx (64) ^((-1)/3`So,
`(1/9) ^((-1)/2) xx (64) ^((-1)/3` = `(1/9) ^((-1)/2) xx (64) ^((-1)/3`,
`= (1/3) ^((-1)/2) xx (4^3) ^((-1)/3) `
`= (1/3^(2 xx (-1)/2)) xx (4^(3 xx (-1)/3))`
`= (1/3^(2 xx (-1)/2)) xx (4^(3 xx (-1)/3))`
`(1/9) ^((-1)/2) xx (64) ^((-1)/3 ) = 1/3^(-1) xx 4^(-1) `
`=1/(1/3) xx 1/4`
`= 1xx 3/1 xx 1/4`
`= 3/4`
Hence the value of the value of `(1/9)^(-1/2) xx (64)^(-1/3)` is `3/4`.
APPEARS IN
संबंधित प्रश्न
Find:-
`9^(3/2)`
Simplify the following
`(a^(3n-9))^6/(a^(2n-4))`
Given `4725=3^a5^b7^c,` find
(i) the integral values of a, b and c
(ii) the value of `2^-a3^b7^c`
Prove that:
`((0.6)^0-(0.1)^-1)/((3/8)^-1(3/2)^3+((-1)/3)^-1)=(-3)/2`
Show that:
`1/(1+x^(a-b))+1/(1+x^(b-a))=1`
Show that:
`(x^(a-b))^(a+b)(x^(b-c))^(b+c)(x^(c-a))^(c+a)=1`
If `3^(4x) = (81)^-1` and `10^(1/y)=0.0001,` find the value of ` 2^(-x+4y)`.
For any positive real number x, write the value of \[\left\{ \left( x^a \right)^b \right\}^\frac{1}{ab} \left\{ \left( x^b \right)^c \right\}^\frac{1}{bc} \left\{ \left( x^c \right)^a \right\}^\frac{1}{ca}\]
If \[\frac{2^{m + n}}{2^{n - m}} = 16\], \[\frac{3^p}{3^n} = 81\] and \[a = 2^{1/10}\],than \[\frac{a^{2m + n - p}}{( a^{m - 2n + 2p} )^{- 1}} =\]
If \[x + \sqrt{15} = 4,\] then \[x + \frac{1}{x}\] =
