Advertisements
Advertisements
प्रश्न
Simplify:
`(16^(-1/5))^(5/2)`
Advertisements
उत्तर
Given `(16^(-1/5))^(5/2)`
`(16^(-1/5))^(5/2)=16^(-1/5xx5/2)`
`=16^(-1/2)`
By using law of rational exponents `a^-n=1/a^n` we have
`(16^(-1/5))^(5/2)=1/16^(1/2)`
`=1/4^(2xx1/2)`
`=1/4`
Hence the value of `(16^(-1/5))^(5/2)` is `1/4`
APPEARS IN
संबंधित प्रश्न
If a = 3 and b = -2, find the values of :
ab + ba
Simplify:
`(sqrt2/5)^8div(sqrt2/5)^13`
Simplify:
`((5^-1xx7^2)/(5^2xx7^-4))^(7/2)xx((5^-2xx7^3)/(5^3xx7^-5))^(-5/2)`
Find the value of x in the following:
`(2^3)^4=(2^2)^x`
If `3^(4x) = (81)^-1` and `10^(1/y)=0.0001,` find the value of ` 2^(-x+4y)`.
Solve the following equation:
`4^(x-1)xx(0.5)^(3-2x)=(1/8)^x`
If a and b are distinct primes such that `root3 (a^6b^-4)=a^xb^(2y),` find x and y.
If a, m, n are positive ingegers, then \[\left\{ \sqrt[m]{\sqrt[n]{a}} \right\}^{mn}\] is equal to
If \[\frac{2^{m + n}}{2^{n - m}} = 16\], \[\frac{3^p}{3^n} = 81\] and \[a = 2^{1/10}\],than \[\frac{a^{2m + n - p}}{( a^{m - 2n + 2p} )^{- 1}} =\]
If \[x = \sqrt{6} + \sqrt{5}\],then \[x^2 + \frac{1}{x^2} - 2 =\]
