Advertisements
Advertisements
प्रश्न
Find the value of x in the following:
`5^(x-2)xx3^(2x-3)=135`
Advertisements
उत्तर
Given `5^(x-2)xx3^(2x-3)=135`
`5^(x-2)xx3^(2x-3)=5xx3^3`
On equating the exponents of 5 and 3 we get,
x - 2 = 1
x = 1 + 2
x = 3
And,
2x - 3 = 3
2x = 3 + 3
2x = 6
x = 6/2
x = 3
Hence, the value of x = 3.
APPEARS IN
संबंधित प्रश्न
Solve the following equation for x:
`2^(5x+3)=8^(x+3)`
Simplify:
`(0.001)^(1/3)`
Prove that:
`sqrt(3xx5^-3)divroot3(3^-1)sqrt5xxroot6(3xx5^6)=3/5`
If a and b are different positive primes such that
`(a+b)^-1(a^-1+b^-1)=a^xb^y,` find x + y + 2.
If `2^x xx3^yxx5^z=2160,` find x, y and z. Hence, compute the value of `3^x xx2^-yxx5^-z.`
Write \[\left( \frac{1}{9} \right)^{- 1/2} \times (64 )^{- 1/3}\] as a rational number.
The value of x − yx-y when x = 2 and y = −2 is
If \[x + \sqrt{15} = 4,\] then \[x + \frac{1}{x}\] =
If \[\frac{5 - \sqrt{3}}{2 + \sqrt{3}} = x + y\sqrt{3}\] , then
Find:-
`32^(2/5)`
