Advertisements
Advertisements
प्रश्न
The positive square root of \[7 + \sqrt{48}\] is
विकल्प
\[7 + 2\sqrt{3}\]
\[7 + \sqrt{3}\]
\[ \sqrt{3}+2\]
\[3 + \sqrt{2}\]
Advertisements
उत्तर
Given that:`7 +sqrt48`.To find square root of the given expression we need to rewrite the expression in the form `a^2 +b^2 +2ab = (a+b)^2`
`7 +sqrt48 = 3+4+2xx2xxsqrt3`
` = (sqrt3)^2 + (2)^2 +2 xx 2xx xxsqrt3`
`= (sqrt3 + 2 )^2`
Hence the square root of the given expression is `sqrt3+2`
APPEARS IN
संबंधित प्रश्न
Find:-
`9^(3/2)`
Simplify:-
`2^(2/3). 2^(1/5)`
If a = 3 and b = -2, find the values of :
ab + ba
Prove that:
`1/(1 + x^(b - a) + x^(c - a)) + 1/(1 + x^(a - b) + x^(c - b)) + 1/(1 + x^(b - c) + x^(a - c)) = 1`
Simplify:
`(0.001)^(1/3)`
Prove that:
`9^(3/2)-3xx5^0-(1/81)^(-1/2)=15`
Find the value of x in the following:
`(sqrt(3/5))^(x+1)=125/27`
Solve the following equation:
`sqrt(a/b)=(b/a)^(1-2x),` where a and b are distinct primes.
Simplify:
`(x^(a+b)/x^c)^(a-b)(x^(b+c)/x^a)^(b-c)(x^(c+a)/x^b)^(c-a)`
If `x = a^(m + n), y = a^(n + l)` and `z = a^(l + m),` prove that `x^my^nz^l = x^ny^lz^m`
