Advertisements
Advertisements
प्रश्न
Find the value of x in the following:
`2^(x-7)xx5^(x-4)=1250`
Advertisements
उत्तर
Given `2^(x-7)xx5^(x-4)=1250`
`2^(x-7)xx5^(x-4)=2^1xx625`
`2^(x-7)xx5^(x-4)=2^1xx5^4`
On equating the exponents we get,
x - 7 = 1
x = 7 + 1
x = 8
And,
x - 4 = 4
x = 4 + 4
x = 8
Hence, the value of x = 8.
APPEARS IN
संबंधित प्रश्न
Simplify the following
`((x^2y^2)/(a^2b^3))^n`
If `a=xy^(p-1), b=xy^(q-1)` and `c=xy^(r-1),` prove that `a^(q-r)b^(r-p)c^(p-q)=1`
Prove that:
`(64/125)^(-2/3)+1/(256/625)^(1/4)+(sqrt25/root3 64)=65/16`
Solve the following equation:
`8^(x+1)=16^(y+2)` and, `(1/2)^(3+x)=(1/4)^(3y)`
Write the value of \[\sqrt[3]{125 \times 27}\].
If a, b, c are positive real numbers, then \[\sqrt{a^{- 1} b} \times \sqrt{b^{- 1} c} \times \sqrt{c^{- 1} a}\] is equal to
If 9x+2 = 240 + 9x, then x =
If x is a positive real number and x2 = 2, then x3 =
The value of 64-1/3 (641/3-642/3), is
Simplify:-
`(1/3^3)^7`
