Advertisements
Advertisements
प्रश्न
If `5^(3x)=125` and `10^y=0.001,` find x and y.
Advertisements
उत्तर
It is given that `5^(3x)=125` and `10^y=0.001`.
Now,
`5^(3x)=125`
`rArr5^(3x)=5^3`
`rArr3x = 3`
x = 1
And,
`10^y=0.001`
`rArr10^y=1/1000`
`rArr10^y=10^-3`
⇒ y = -3
hence, the value of x and yare 1 and -3, respectively.
APPEARS IN
संबंधित प्रश्न
Simplify the following
`3(a^4b^3)^10xx5(a^2b^2)^3`
Simplify the following
`((4xx10^7)(6xx10^-5))/(8xx10^4)`
If abc = 1, show that `1/(1+a+b^-1)+1/(1+b+c^-1)+1/(1+c+a^-1)=1`
Given `4725=3^a5^b7^c,` find
(i) the integral values of a, b and c
(ii) the value of `2^-a3^b7^c`
Assuming that x, y, z are positive real numbers, simplify the following:
`(sqrt(x^-3))^5`
Solve the following equation:
`3^(x+1)=27xx3^4`
Which one of the following is not equal to \[\left( \frac{100}{9} \right)^{- 3/2}\]?
If a, b, c are positive real numbers, then \[\sqrt{a^{- 1} b} \times \sqrt{b^{- 1} c} \times \sqrt{c^{- 1} a}\] is equal to
The value of \[\frac{\sqrt{48} + \sqrt{32}}{\sqrt{27} + \sqrt{18}}\] is
If \[\frac{5 - \sqrt{3}}{2 + \sqrt{3}} = x + y\sqrt{3}\] , then
