Advertisements
Advertisements
प्रश्न
\[\frac{5^{n + 2} - 6 \times 5^{n + 1}}{13 \times 5^n - 2 \times 5^{n + 1}}\] is equal to
पर्याय
\[\frac{5}{3}\]
\[- \frac{5}{3}\]
\[\frac{3}{5}\]
\[- \frac{3}{5}\]
Advertisements
उत्तर
We have to simplify `(5^(n+2) - 6xx 5^(n+1))/(13 xx 5^n - 2 xx5^(n+1))`
Taking `5^2` as a common factor we get
`(5^(n+2) - 6xx 5^(n+1))/(13 xx 5^n - 2 xx5^(n+1)) = (5^n(5^2 -6 xx 5^1))/(5^n(13-2 xx 5^1))`
`= (5^n(25-30))/(5^n(13-10))`
` = (-5)/3`
APPEARS IN
संबंधित प्रश्न
Simplify:-
`2^(2/3). 2^(1/5)`
Solve the following equation for x:
`4^(x-1)xx(0.5)^(3-2x)=(1/8)^x`
If `a=xy^(p-1), b=xy^(q-1)` and `c=xy^(r-1),` prove that `a^(q-r)b^(r-p)c^(p-q)=1`
Show that:
`(a^(x+1)/a^(y+1))^(x+y)(a^(y+2)/a^(z+2))^(y+z)(a^(z+3)/a^(x+3))^(z+x)=1`
Solve the following equation:
`3^(x-1)xx5^(2y-3)=225`
State the quotient law of exponents.
The seventh root of x divided by the eighth root of x is
If a, b, c are positive real numbers, then \[\sqrt{a^{- 1} b} \times \sqrt{b^{- 1} c} \times \sqrt{c^{- 1} a}\] is equal to
If 10x = 64, what is the value of \[{10}^\frac{x}{2} + 1 ?\]
Find:-
`125^(1/3)`
