Advertisements
Advertisements
प्रश्न
\[\frac{5^{n + 2} - 6 \times 5^{n + 1}}{13 \times 5^n - 2 \times 5^{n + 1}}\] is equal to
विकल्प
\[\frac{5}{3}\]
\[- \frac{5}{3}\]
\[\frac{3}{5}\]
\[- \frac{3}{5}\]
Advertisements
उत्तर
We have to simplify `(5^(n+2) - 6xx 5^(n+1))/(13 xx 5^n - 2 xx5^(n+1))`
Taking `5^2` as a common factor we get
`(5^(n+2) - 6xx 5^(n+1))/(13 xx 5^n - 2 xx5^(n+1)) = (5^n(5^2 -6 xx 5^1))/(5^n(13-2 xx 5^1))`
`= (5^n(25-30))/(5^n(13-10))`
` = (-5)/3`
APPEARS IN
संबंधित प्रश्न
Simplify:-
`2^(2/3). 2^(1/5)`
Prove that:
`(x^a/x^b)^cxx(x^b/x^c)^axx(x^c/x^a)^b=1`
Assuming that x, y, z are positive real numbers, simplify the following:
`sqrt(x^3y^-2)`
Show that:
`[{x^(a(a-b))/x^(a(a+b))}div{x^(b(b-a))/x^(b(b+a))}]^(a+b)=1`
If 2x = 3y = 12z, show that `1/z=1/y+2/x`
Find the value of x in the following:
`5^(2x+3)=1`
For any positive real number x, find the value of \[\left( \frac{x^a}{x^b} \right)^{a + b} \times \left( \frac{x^b}{x^c} \right)^{b + c} \times \left( \frac{x^c}{x^a} \right)^{c + a}\].
If 102y = 25, then 10-y equals
If x= \[\frac{\sqrt{3} - \sqrt{2}}{\sqrt{3} + \sqrt{2}}\] and y = \[\frac{\sqrt{3} + \sqrt{2}}{\sqrt{3} - \sqrt{2}}\] , then x2 + y +y2 =
If `a = 2 + sqrt(3)`, then find the value of `a - 1/a`.
