Advertisements
Advertisements
प्रश्न
If 10x = 64, what is the value of \[{10}^\frac{x}{2} + 1 ?\]
विकल्प
18
42
80
81
Advertisements
उत्तर
We have to find the value of `10^(x/2+1)`provided `10^x = 64`
So,
`10^(x/2 xx 1) = 10^(x xx1/2) xx 10^1`
`= 2sqrt(10^x) xx 10^1`
By substituting `10x = 64 `we get
`=2sqrt 64 xx 10^1`
`=2sqrt (8xx8 )xx10`
`=8xx10`
`= 80`
APPEARS IN
संबंधित प्रश्न
Solve the following equation for x:
`7^(2x+3)=1`
Solve the following equation for x:
`2^(3x-7)=256`
Solve the following equations for x:
`3^(2x+4)+1=2.3^(x+2)`
If ax = by = cz and b2 = ac, show that `y=(2zx)/(z+x)`
Solve the following equation:
`4^(2x)=(root3 16)^(-6/y)=(sqrt8)^2`
State the power law of exponents.
If \[\frac{x}{x^{1 . 5}} = 8 x^{- 1}\] and x > 0, then x =
The value of 64-1/3 (641/3-642/3), is
The value of \[\sqrt{3 - 2\sqrt{2}}\] is
The value of \[\sqrt{5 + 2\sqrt{6}}\] is
