Advertisements
Advertisements
प्रश्न
If 3x = 5y = (75)z, show that `z=(xy)/(2x+y)`
Advertisements
उत्तर
Let 3x = 5y = (75)z = k
`rArr3=k^(1/x),` `5=k^(1/y),` `75=k^(1/z)`
`rArr5^2xx3=k^(1/z)`
`rArr(k^(1/y))^2xxk^(1/x)=k^(1/z)`
`rArrk^(2/y)xxk^(1/x)=k^(1/z)`
`rArrk^(2/y+1/x)=k^(1/z)`
`rArr2/y+1/x=1/z`
`rArr(2x+y)/(xy)=1/z`
`rArrz=(xy)/(2x+y)`
APPEARS IN
संबंधित प्रश्न
Simplify the following
`(a^(3n-9))^6/(a^(2n-4))`
Show that:
`1/(1+x^(a-b))+1/(1+x^(b-a))=1`
Show that:
`(x^(a-b))^(a+b)(x^(b-c))^(b+c)(x^(c-a))^(c+a)=1`
Find the value of x in the following:
`(13)^(sqrtx)=4^4-3^4-6`
If `3^(4x) = (81)^-1` and `10^(1/y)=0.0001,` find the value of ` 2^(-x+4y)`.
Solve the following equation:
`4^(x-1)xx(0.5)^(3-2x)=(1/8)^x`
State the product law of exponents.
Write the value of \[\sqrt[3]{125 \times 27}\].
Which of the following is (are) not equal to \[\left\{ \left( \frac{5}{6} \right)^{1/5} \right\}^{- 1/6}\] ?
\[\frac{1}{\sqrt{9} - \sqrt{8}}\] is equal to
