Advertisements
Advertisements
प्रश्न
Solve the following equation:
`3^(x-1)xx5^(2y-3)=225`
Advertisements
उत्तर
`3^(x-1)xx5^(2y-3)=225`
`rArr3^(x-1)xx5^(2y-3)=3xx3xx5xx5`
`rArr3^(x-1)xx5^(2y-3)=3^2xx5^2`
⇒ x - 1 = 2 and 2y - 3 = 2
⇒ x = 2 + 1 and 2y = 2 + 3
⇒ x = 3 and 2y = 5
⇒ x = 3 and y = 5/2
APPEARS IN
संबंधित प्रश्न
If abc = 1, show that `1/(1+a+b^-1)+1/(1+b+c^-1)+1/(1+c+a^-1)=1`
Solve the following equation for x:
`4^(x-1)xx(0.5)^(3-2x)=(1/8)^x`
If 49392 = a4b2c3, find the values of a, b and c, where a, b and c are different positive primes.
Simplify:
`((25)^(3/2)xx(243)^(3/5))/((16)^(5/4)xx(8)^(4/3))`
Simplify:
`(sqrt2/5)^8div(sqrt2/5)^13`
If `5^(3x)=125` and `10^y=0.001,` find x and y.
Solve the following equation:
`4^(x-1)xx(0.5)^(3-2x)=(1/8)^x`
State the product law of exponents.
If \[\frac{3^{2x - 8}}{225} = \frac{5^3}{5^x},\] then x =
If \[2^{- m} \times \frac{1}{2^m} = \frac{1}{4},\] then \[\frac{1}{14}\left\{ ( 4^m )^{1/2} + \left( \frac{1}{5^m} \right)^{- 1} \right\}\] is equal to
