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Question
Find the value of x in the following:
`2^(5x)div2x=root5(2^20)`
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Solution
Given `2^(5x)div2x=root5(2^20)`
By using rational exponents `a^m/a^n=a^(m-n)` we get,
`2^(5x-x)=2^(20xx1/5)`
`2^(5x-x)=2^4`
On equating the exponents we get,
5x - x = 4
4x = 4
x = 4/4
x = 1
The value of x = 1
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