Advertisements
Advertisements
Question
Find the value of x in the following:
`(2^3)^4=(2^2)^x`
Advertisements
Solution
Given `(2^3)^4=(2^2)^x`
`2^(3xx4)=2^(2xx x)`
`2^12=2^(2x)`
On equating the exponents
12 = 2x
x = 12/2
x = 6
Hence, the value of x = 6.
APPEARS IN
RELATED QUESTIONS
Solve the following equation for x:
`4^(x-1)xx(0.5)^(3-2x)=(1/8)^x`
Prove that:
`(1/4)^-2-3xx8^(2/3)xx4^0+(9/16)^(-1/2)=16/3`
Prove that:
`(2^(1/2)xx3^(1/3)xx4^(1/4))/(10^(-1/5)xx5^(3/5))div(3^(4/3)xx5^(-7/5))/(4^(-3/5)xx6)=10`
Prove that:
`(2^n+2^(n-1))/(2^(n+1)-2^n)=3/2`
If ax = by = cz and b2 = ac, show that `y=(2zx)/(z+x)`
Find the value of x in the following:
`(sqrt(3/5))^(x+1)=125/27`
If `3^(x+1)=9^(x-2),` find the value of `2^(1+x)`
Solve the following equation:
`4^(2x)=(root3 16)^(-6/y)=(sqrt8)^2`
Solve the following equation:
`8^(x+1)=16^(y+2)` and, `(1/2)^(3+x)=(1/4)^(3y)`
If (x − 1)3 = 8, What is the value of (x + 1)2 ?
