Advertisements
Advertisements
Question
Find the value of x in the following:
`(2^3)^4=(2^2)^x`
Advertisements
Solution
Given `(2^3)^4=(2^2)^x`
`2^(3xx4)=2^(2xx x)`
`2^12=2^(2x)`
On equating the exponents
12 = 2x
x = 12/2
x = 6
Hence, the value of x = 6.
shaalaa.com
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Simplify the following:
`(5xx25^(n+1)-25xx5^(2n))/(5xx5^(2n+3)-25^(n+1))`
Solve the following equation for x:
`2^(5x+3)=8^(x+3)`
Simplify:
`((5^-1xx7^2)/(5^2xx7^-4))^(7/2)xx((5^-2xx7^3)/(5^3xx7^-5))^(-5/2)`
Prove that:
`(2^n+2^(n-1))/(2^(n+1)-2^n)=3/2`
Prove that:
`(3^-3xx6^2xxsqrt98)/(5^2xxroot3(1/25)xx(15)^(-4/3)xx3^(1/3))=28sqrt2`
Show that:
`(x^(1/(a-b)))^(1/(a-c))(x^(1/(b-c)))^(1/(b-a))(x^(1/(c-a)))^(1/(c-b))=1`
If 2x = 3y = 6-z, show that `1/x+1/y+1/z=0`
Write the value of \[\sqrt[3]{125 \times 27}\].
If x = \[\frac{2}{3 + \sqrt{7}}\],then (x−3)2 =
Find:-
`125^((-1)/3)`
