Advertisements
Advertisements
प्रश्न
Find the value of x in the following:
`(2^3)^4=(2^2)^x`
Advertisements
उत्तर
Given `(2^3)^4=(2^2)^x`
`2^(3xx4)=2^(2xx x)`
`2^12=2^(2x)`
On equating the exponents
12 = 2x
x = 12/2
x = 6
Hence, the value of x = 6.
APPEARS IN
संबंधित प्रश्न
Simplify the following
`((x^2y^2)/(a^2b^3))^n`
If 49392 = a4b2c3, find the values of a, b and c, where a, b and c are different positive primes.
Given `4725=3^a5^b7^c,` find
(i) the integral values of a, b and c
(ii) the value of `2^-a3^b7^c`
Find the value of x in the following:
`(3/5)^x(5/3)^(2x)=125/27`
Find the value of x in the following:
`5^(x-2)xx3^(2x-3)=135`
Solve the following equation:
`3^(x-1)xx5^(2y-3)=225`
If \[8^{x + 1}\] = 64 , what is the value of \[3^{2x + 1}\] ?
If \[2^{- m} \times \frac{1}{2^m} = \frac{1}{4},\] then \[\frac{1}{14}\left\{ ( 4^m )^{1/2} + \left( \frac{1}{5^m} \right)^{- 1} \right\}\] is equal to
Simplify:
`(1^3 + 2^3 + 3^3)^(1/2)`
Simplify:
`(9^(1/3) xx 27^(-1/2))/(3^(1/6) xx 3^(- 2/3))`
