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Question
If (x − 1)3 = 8, What is the value of (x + 1)2 ?
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Solution
We have to find the value of , `(x+1)^2`where `(x-1)^3 = 8`
Consider `(x-1)^3 =2^3`
By equating the base, we get
x-1 = 2
x=2+1
x = 3
By substituting x = 3in `(x+1)^2`
`= (x+1)^2`
`=(3+1)^2`
`=4^2`
`= 4 xx 4 `
=1 6
Hence the value of `(x+1)^2` is 16.
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