Advertisements
Advertisements
प्रश्न
Simplify:
`root(lm)(x^l/x^m)xxroot(mn)(x^m/x^n)xxroot(nl)(x^n/x^l)`
Advertisements
उत्तर
`root(lm)(x^l/x^m)xxroot(mn)(x^m/x^n)xxroot(nl)(x^n/x^l)`
`=(x^l/x^m)^(1/(lm))xx(x^m/x^n)^(1/(mn))xx(x^n/x^l)^(1/(nl))`
`=(x^(l-m))^(1/ml)xx(x^(m-n))^(1/mn)xx(x^(n-l))^(1/)nl`
`=x^((l-m)/(ml))xx x^((m-n)/(mn))xx x^((n-l)/(nl))`
`=x^((l-m)/(ml)+(m-n)/(mn)+(n-l)/(nl))`
`=x^((ln-mn+lm-nl+nm-lm)/(nml))`
`=x^0`
= 1
APPEARS IN
संबंधित प्रश्न
If `a=xy^(p-1), b=xy^(q-1)` and `c=xy^(r-1),` prove that `a^(q-r)b^(r-p)c^(p-q)=1`
Show that:
`(x^(a-b))^(a+b)(x^(b-c))^(b+c)(x^(c-a))^(c+a)=1`
Simplify \[\left[ \left\{ \left( 625 \right)^{- 1/2} \right\}^{- 1/4} \right]^2\]
If (23)2 = 4x, then 3x =
If x-2 = 64, then x1/3+x0 =
(256)0.16 × (256)0.09
If x is a positive real number and x2 = 2, then x3 =
If \[x = \frac{\sqrt{5} + \sqrt{3}}{\sqrt{5} - \sqrt{3}}\] and \[y = \frac{\sqrt{5} - \sqrt{3}}{\sqrt{5} + \sqrt{3}}\] then x + y +xy=
The value of \[\frac{\sqrt{48} + \sqrt{32}}{\sqrt{27} + \sqrt{18}}\] is
Find:-
`32^(2/5)`
