Advertisements
Advertisements
Question
Find the value to three places of decimals of the following. It is given that
`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`
`(2 + sqrt3)/3`
Advertisements
Solution
Given that `(2 + sqrt3)/2`
Putting the value of `sqrt3` we get
`(2 + sqrt3)/2 = (2 + 1.732)/2`
`= 3.732/2`
= 1.24401
The value of expression 1.24401 can be round off to three decimal places as 1.244.
Hence the given expression is simplified to 1.244
APPEARS IN
RELATED QUESTIONS
if `x= 3 + sqrt8`, find the value of `x^2 + 1/x^2`
Write the rationalisation factor of \[7 - 3\sqrt{5}\].
The rationalisation factor of \[2 + \sqrt{3}\] is
Classify the following number as rational or irrational:
`(2sqrt7)/(7sqrt7)`
Classify the following number as rational or irrational:
2π
Rationalise the denominator of the following:
`1/(sqrt5+sqrt2)`
The number obtained on rationalising the denominator of `1/(sqrt(7) - 2)` is ______.
Simplify the following:
`4sqrt12 xx 7sqrt6`
Rationalise the denominator of the following:
`2/(3sqrt(3)`
Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`6/sqrt(6)`
