#### Online Mock Tests

#### Chapters

Chapter 2: Inverse Trigonometric Functions

Chapter 3: Matrices

Chapter 4: Determinants

Chapter 5: Continuity and Differentiability

Chapter 6: Application of Derivatives

Chapter 7: Integrals

Chapter 8: Application of Integrals

Chapter 9: Differential Equations

Chapter 10: Vector Algebra

Chapter 11: Three Dimensional Geometry

Chapter 12: Linear Programming

Chapter 13: Probability

## Solutions for Chapter 8: Application of Integrals

Below listed, you can find solutions for Chapter 8 of CBSE, Karnataka Board PUC NCERT for Class 12 Maths.

### NCERT solutions for Class 12 Maths Chapter 8 Application of Integrals Exercise 8.1 [Pages 365 - 366]

Find the area of the region bounded by the curve *y*^{2} = *x* and the lines *x* = 1, *x* = 4 and the *x*-axis.

Find the area of the region bounded by *y*^{2} = 9*x*,* x* = 2, *x* = 4 and the *x*-axis in the first quadrant.

Find the area of the region bounded by *x*^{2} = 4*y*, *y* = 2, *y* = 4 and the *y*-axis in the first quadrant.

Find the area of the region bounded by the ellipse `x^2/16 + y^2/9 = 1`

Find the area of the region bounded by the ellipse `x^2/4 + y^2/9 = 1`

Find the area of the region in the first quadrant enclosed by x-axis, line x = `sqrt3` y and the circle x^{2} + y^{2} = 4.

Find the area of the smaller part of the circle *x*^{2} +* y*^{2} = *a*^{2} cut off by the line `x = a/sqrt2`

The area between *x* = *y*^{2} and *x* = 4 is divided into two equal parts by the line *x* = *a*, find the value of *a*.

Find the area of the region bounded by the parabola y = x2 and y = |x| .

Find the area bounded by the curve *x*^{2} = 4*y* and the line *x* = 4*y *– 2

Find the area of the region bounded by the curve *y*^{2} = 4*x* and the line *x* = 3

Area lying in the first quadrant and bounded by the circle *x*^{2} + *y*^{2} = 4 and the lines *x* = 0 and *x *= 2 is

**A.** π

**B.** `pi/2`

**C.** `pi/3`

**D. `pi/4`**

Area of the region bounded by the curve *y*^{2} = 4*x*, *y*-axis and the line *y* = 3 is

**A.** 2

**B.** 9/4

**C.** 9/3

**D. 9/2**

### NCERT solutions for Class 12 Maths Chapter 8 Application of Integrals Exercise 8.2 [Pages 371 - 372]

Find the area of the circle 4*x*^{2} + 4*y*^{2} = 9 which is interior to the parabola *x*^{2} = 4*y*

Find the area bounded by curves (*x* – 1)^{2} + *y*^{2} = 1 and *x*^{2} + *y*^{ 2} = 1

Find the area of the region bounded by the curves *y* = *x*^{2 }+ 2, *y *= *x*, *x* = 0 and *x* = 3

Using integration finds the area of the region bounded by the triangle whose vertices are (–1, 0), (1, 3) and (3, 2).

Using integration find the area of the triangular region whose sides have the equations *y* = 2*x* +1, *y* = 3*x* + 1 and *x *= 4.

Smaller area enclosed by the circle *x*^{2} + *y*^{2} = 4 and the line *x* + *y* = 2 is

**A.** 2 (π – 2)

**B.** π – 2

**C.** 2π – 1

**D. **2 (π + 2)

Area lying between the curve *y*^{2} = 4*x* and *y* = 2*x* is

**A.** 2/3

**B.** 1/3

**C.** 1/4

**D. 3/4**

### NCERT solutions for Class 12 Maths Chapter 8 Application of Integrals Exercise 8.3 [Pages 375 - 376]

Find the area under the given curves and given lines:

*y* = *x*^{2}, *x* = 1, *x* = 2 and *x*-axis

Find the area under the given curves and given lines:

*y* = *x*^{4}, *x* = 1, *x* = 5 and *x* –axis

Find the area between the curves *y* = *x* and *y* = *x*^{2}

Find the area of the region lying in the first quadrant and bounded by *y* = 4*x*^{2}, *x* = 0, *y* = 1 and *y *= 4

Sketch the graph of y = |x + 3| and evaluate `int_(-6)^0 |x + 3|dx`

Find the area bounded by the curve *y* = sin *x *between *x* = 0 and *x* = 2π

Find the area enclosed between the parabola *y*^{2} = 4*ax* and the line* y *= *mx*

Find the area enclosed by the parabola 4*y* = 3*x*^{2} and the line 2*y* = 3*x* + 12

Find the area of the smaller region bounded by the ellipse `x^2/9 + y^2/4` and the line `x/3 + y/2 = 1`

Find the area of the smaller region bounded by the ellipse `x^2/a^2 + y^2/b^2 = 1` and the line `x/a + y/b = 1`

Find the area of the region enclosed by the parabola *x*^{2} = *y*, the line *y* = *x* + 2 and *x*-axis

Using the method of integration find the area bounded by the curve |x| + |y| = 1 .

[Hint: The required region is bounded by lines x + y = 1, x– y = 1, – x + y = 1 and

– x – y = 1].

Find the area bounded by curves {(x, y) : y ≥ x2 and y = |x|}.

Using the method of integration find the area of the triangle ABC, coordinates of whose vertices are A(2, 0), B (4, 5) and C (6, 3).

Using the method of integration find the area of the region bounded by lines: 2*x* + *y* = 4, 3*x* – 2*y* = 6 and *x* – 3*y *+ 5 = 0

Find the area of the region {(x, y) : y2 ≤ 4x, 4x2 + 4y2 ≤ 9}

Choose the correct answer Area bounded by the curve *y* = *x*^{3}, the *x*-axis and the ordinates *x* = –2 and *x* = 1 is

**A.** – 9

**B.** `-15/4`

**C.** `15/4`

**D. `17/4`**

Choose the correct answer The area bounded by the curve y = x | x| ,, *x*-axis and the ordinates *x* = –1 and *x* = 1 is given by

**[Hint:** *y* = *x*^{2} if *x* > 0 and *y* = –*x*^{2} if *x* < 0]

**A.** 0

**B.** `1/3`

**C.** `2/3`

**D. `4/3`**

Choose the correct answer The area of the circle *x*^{2} + *y*^{2} = 16 exterior to the parabola *y*^{2} = 6*x* is

A. `4/3 (4pi - sqrt3)`

B. `4/3 (4pi + sqrt3)`

C. `4/3 (8pi - sqrt3)`

D.`4/3 (4pi + sqrt3)`

The area bounded by the *y*-axis, *y* = cos *x* and* y *= sin *x* when 0 <= x <= `pi/2`

(A) 2 ( 2 −1)

(B) `sqrt2 -1`

(C) `sqrt2 + 1`

D. `sqrt2`

## Solutions for Chapter 8: Application of Integrals

## NCERT solutions for Class 12 Maths chapter 8 - Application of Integrals

Shaalaa.com has the CBSE, Karnataka Board PUC Mathematics Class 12 Maths CBSE, Karnataka Board PUC solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. NCERT solutions for Mathematics Class 12 Maths CBSE, Karnataka Board PUC 8 (Application of Integrals) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.

Further, we at Shaalaa.com provide such solutions so students can prepare for written exams. NCERT textbook solutions can be a core help for self-study and provide excellent self-help guidance for students.

Concepts covered in Class 12 Maths chapter 8 Application of Integrals are Area of the Region Bounded by a Curve and a Line, Area Between Two Curves, Area Under Simple Curves.

Using NCERT Class 12 Maths solutions Application of Integrals exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in NCERT Solutions are essential questions that can be asked in the final exam. Maximum CBSE, Karnataka Board PUC Class 12 Maths students prefer NCERT Textbook Solutions to score more in exams.

Get the free view of Chapter 8, Application of Integrals Class 12 Maths additional questions for Mathematics Class 12 Maths CBSE, Karnataka Board PUC, and you can use Shaalaa.com to keep it handy for your exam preparation.