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Karnataka Board PUCPUC Science Class 11

The driver of a three-wheeler moving with a speed of 36 km/h sees a child standing in the middle of the road and brings his vehicle to rest in 4.0 s just in time to - Physics

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Question

The driver of a three-wheeler moving with a speed of 36 km/h sees a child standing in the middle of the road and brings his vehicle to rest in 4.0 s just in time to save the child. What is the average retarding force on the vehicle? The mass of the three-wheeler is 400 kg and the mass of the driver is 65 kg.

Numerical
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Solution

Initial speed of the three-wheeler, u = 36 km/h

= 36 × (5/18) m/s

= 10 m/s

Final speed of the three-wheeler, v = 0 m/s

Time, t = 4 s

Mass of the three-wheeler, m = 400 kg

Mass of the driver, m' = 65 kg

Total mass of the system, M = 400 + 65 = 465 kg

Using the first law of motion, the acceleration (a) of the three-wheeler can be calculated as:

v = u + at

`:. a =(v-u)/t = (0 - 10)/4 = -2.5 "m/s"^2`

The negative sign signifies that the velocity of the three-wheeler is reducing over time.

Using Newton’s second law of motion, the net force acting on the three-wheeler can be calculated as:

F = Ma

= 465 × (-2.5) = -1162.5 N = 1.2 × 103 N

The negative sign suggests that the force is applied in opposition to the direction of motion of the three-wheeler.

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Chapter 4: Laws of Motion - EXERCISES [Page 69]

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NCERT Physics [English] Class 11
Chapter 4 Laws of Motion
EXERCISES | Q 4.8 | Page 69

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