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Solve the following differential equation: y log y = (log y2 - x) dydxdydx

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Question

Solve the following differential equation:

y log y = (log y2 - x) `"dy"/"dx"`

Sum
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Solution

y log y = (log y2 - x) `"dy"/"dx"`

∴ `1/("dy"/"dx") = (log "y"^2 - "x")/("y" log "y")`

∴ `"dx"/"dy" = (2 log "y - x")/("y" log "y")`

∴ `"dx"/"dy" = 2/"y" - "x"/("y" log "y")`

∴ `"dx"/"dy" + "x"/("y" log "y") = 2/"y"`    .....(1)

This is the linear differential equation of the form

`"dx"/"dy" + "Px" = "Q"` where P = `1/("y" log "y") and "Q" = 2/"y"`

∴ I.F. = `"e"^(int "P dy") = "e"^(int 1/("y" log "y")"dy")`

`= "e"^(int (1//"y")/(log "y")"dy") = "e"^(log |log "y"|)` = log y

∴ the solution of (1) is given by

`"x" * ("I.F.") = int "Q" * ("I.F.") "dy" + "c"`

∴ `"x" * log "y" = int 2/"y" * log "y"  "dy" + "c"`

∴ `(log "y") * "x" = 2 int (log "y")/"y" "dy" + "c"`

Put log y = t

∴ `1/"y" "dy" = "dt"`

∴ `("log y")*"x" = 2 int "t"  "dt" + "c"`

∴ x log y = `2 * "t"^2/2 + "c"`

∴ x log y = (log y)2 + c

This is the general solution.

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Chapter 6: Differential Equations - Miscellaneous exercise 2 [Page 217]

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Balbharati Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
Chapter 6 Differential Equations
Miscellaneous exercise 2 | Q 5.6 | Page 217

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