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Sec 8 a − 1 Sec 4 a − 1 = - Mathematics

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Question

\[\frac{\sec 8A - 1}{\sec 4A - 1} =\]

 

Options

  • \[\frac{\tan 2A}{\tan 8A}\]

     

  • \[\frac{\tan 8A}{\tan 2A}\]

     

  • \[\frac{\cot 8A}{\cot 2A}\]

     

  • none of these.

     
MCQ
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Solution

\[\frac{\tan 8A}{\tan 2A}\] 

\[\text{ We have } , \]
\[\frac{\sec8A - 1}{\sec4A - 1} = \frac{\frac{1}{\cos8A} - 1}{\frac{1}{\cos4A} - 1}\]
\[ = \frac{\cos4A}{\cos8A} \times \frac{1 - \cos8A}{1 - \cos4A}\]
\[= \frac{\cos4A}{\cos8A} \times \frac{2 \sin^2 4A}{2 \sin^2 2A} \left( 2 \sin^2 \theta = 1 - \cos2\theta \right)\]
\[ = \frac{\left( 2\cos4A \sin4A \right) \sin4A}{2 \times \cos8A \sin^2 2A}\]
\[ = \frac{\sin8A \sin4A}{\cos8A \times 2\sin2A \times \sin2A}\]
\[ = \tan8A \times \frac{2\sin2A \times \cos2A}{2\sin2A \times \sin2A}\]
\[ = \tan8A \times \cot2A\]
\[ = \frac{\tan8A}{\tan2A}\]

 

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Values of Trigonometric Functions at Multiples and Submultiples of an Angle
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Chapter 9: Values of Trigonometric function at multiples and submultiples of an angle - Exercise 9.5 [Page 43]

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RD Sharma Mathematics [English] Class 11
Chapter 9 Values of Trigonometric function at multiples and submultiples of an angle
Exercise 9.5 | Q 2 | Page 43

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