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Prove that: 7 π 12 + cos π 12 = sin 5 π 12 − sin π 12

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Question

Prove that:
\[\frac{7\pi}{12} + \cos\frac{\pi}{12} = \sin\frac{5\pi}{12} - \sin\frac{\pi}{12}\]

Answer in Brief
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Solution

\[105^\circ = \frac{7\pi}{12}, 15^\circ = \frac{\pi}{12}, 75^\circ = \frac{5\pi}{12}, 15^\circ = \frac{\pi}{12}\]
LHS = cos105o + cos15o
        = cos(90o + 15o) + cos(90- 75o)
        = - sin 15o + sin 75o [As cos(90o+A) = - sin A and cos(90o- B) = sin B]
        = sin 75o- sin 15o
        = RHS
Hence proved.
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Chapter 7: Values of Trigonometric function at sum or difference of angles - Exercise 7.1 [Page 19]

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R.D. Sharma Mathematics [English] Class 11
Chapter 7 Values of Trigonometric function at sum or difference of angles
Exercise 7.1 | Q 9 | Page 19

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