Advertisements
Advertisements
Question
In ΔPQR, If ∠R > ∠Q then ______.
Options
QR > PR
PQ > PR
PQ < PR
QR < PR
Advertisements
Solution
In ΔPQR, If ∠R > ∠Q then PQ > PR.
APPEARS IN
RELATED QUESTIONS
In a ΔABC, if ∠A = 55°, ∠B = 40°, find ∠C.
In the given figure, AB || DE. Find ∠ACD.

Is the following statement true and false :
A triangle can have at most one obtuse angles.
Fill in the blank to make the following statement true:
An exterior angle of a triangle is always ......... than either of the interior opposite angles.
Define a triangle.
In Δ ABC, if u∠B = 60°, ∠C = 80° and the bisectors of angles ∠ABC and ∠ACB meet at a point O, then find the measure of ∠BOC.
State exterior angle theorem.
In ΔABC, ∠B = ∠C and ray AX bisects the exterior angle ∠DAC. If ∠DAX = 70°, then ∠ACB =
In a triangle PQR, ∠P = 60° and ∠Q = ∠R, find ∠R.
The angle of a vertex of an isosceles triangle is 100°. Find its base angles.
In the given figure, express a in terms of b.

In the following, find the marked unknown angle:


As shown in the figure, Avinash is standing near his house. He can choose from two roads to go to school. Which way is shorter? Explain why.
The length of the three segments is given for constructing a triangle. Say whether a triangle with these sides can be drawn. Give the reason for your answer.
8.4 cm, 16.4 cm, 4.9 cm
The angles of the triangle are 3x – 40, x + 20 and 2x – 10 then the value of x is
In the following figure, AD is the bisector of ∠BAC. Prove that AB > BD.

The image of an object placed at a point A before a plane mirror LM is seen at the point B by an observer at D as shown in the following figure. Prove that the image is as far behind the mirror as the object is in front of the mirror.
[Hint: CN is normal to the mirror. Also, angle of incidence = angle of reflection].

The number of angles in the following figure is ______.

In the following figure, AB = BC and AD = BD = DC. The number of isosceles triangles in the figure is ______.

What is the sum of the measures of the interior angles of any triangle, △ABC?
