Advertisements
Advertisements
Question
In ΔABC, if bisectors of ∠ABC and ∠ACB intersect at O at angle of 120°, then find the measure of ∠A.
Advertisements
Solution
In the given ΔABC, ∠ABC = ∠ACB, the bisectors of ∠ABC and ∠ACBmeet at O and ∠BOC = 120°
We need to find the measure of ∠A

So here, using the corollary, “if the bisectors of ∠ABCand ∠ACBof a ΔABCmeet at a point O, then`∠BOC = 90° + 1/2 ∠A`
Thus, in ΔABC
`∠BOC = 90° + 1/2 ∠A`
` 120° = 90° + 1/2 ∠A`
`120° - 90° + 1/2 ∠A`
∠A = 2(30°)
∠A= 60°
Thus, ∠A = 60°
APPEARS IN
RELATED QUESTIONS
Can a triangle have All angles more than 60°? Justify your answer in case.
Compute the value of x in the following figure:

In the given figure, AE bisects ∠CAD and ∠B= ∠C. Prove that AE || BC.

In the given figure, express a in terms of b.

Can a triangle together have the following angles?
85°, 95° and 22°
In ∆ABC, C = 56° C = 56° ∠B = ∠C and ∠A = 100° ; find ∠B.
The length of the sides of the triangle is given. Say what types of triangles they are 3.7 cm, 3.4 cm, 4 cm.
In a ∆ABC, AB = AC. The value of x is ________
O is a point in the interior of a square ABCD such that OAB is an equilateral triangle. Show that ∆OCD is an isosceles triangle.
The sides of a triangle must always be connected so that:
