Advertisements
Advertisements
प्रश्न
In ΔABC, if bisectors of ∠ABC and ∠ACB intersect at O at angle of 120°, then find the measure of ∠A.
Advertisements
उत्तर
In the given ΔABC, ∠ABC = ∠ACB, the bisectors of ∠ABC and ∠ACBmeet at O and ∠BOC = 120°
We need to find the measure of ∠A

So here, using the corollary, “if the bisectors of ∠ABCand ∠ACBof a ΔABCmeet at a point O, then`∠BOC = 90° + 1/2 ∠A`
Thus, in ΔABC
`∠BOC = 90° + 1/2 ∠A`
` 120° = 90° + 1/2 ∠A`
`120° - 90° + 1/2 ∠A`
∠A = 2(30°)
∠A= 60°
Thus, ∠A = 60°
APPEARS IN
संबंधित प्रश्न
If the bisectors of the base angles of a triangle enclose an angle of 135°, prove that the triangle is a right triangle.
Can a triangle have All angles equal to 60°? Justify your answer in case.
In the given figure, AM ⊥ BC and AN is the bisector of ∠A. If ∠B = 65° and ∠C = 33°, find ∠MAN.

In the given figure, AE bisects ∠CAD and ∠B= ∠C. Prove that AE || BC.

An exterior angle of a triangle is equal to 100° and two interior opposite angles are equal. Each of these angles is equal to
One angle of a triangle is 61° and the other two angles are in the ratio `1 1/2: 1 1/3`. Find these angles.
One of the base angles of an isosceles triangle is 52°. Find its angle of the vertex.
Find, giving a reason, the unknown marked angles, in a triangle drawn below:

Can we have two acute angles whose sum is an acute angle? Why or why not?
Can we have two acute angles whose sum is an obtuse angle? Why or why not?
