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Question
Two angles of a triangle are equal and the third angle is greater than each of those angles
by 30°. Determine all the angles of the triangle.
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Solution
Given that,
Two angles are equal and the third angle is greater than each of those angles `by 30^@` Let x, x, x+30 be the angles of a triangle
We know that
Sum of all angles of a triangle is `180^@`
`x+x+x+30=180^@`
`3x+30=180^@`
`3x=180^@-30^@`
`3x=150^@`
`x=150^@/3`
`x=50^@`
∴ The angles are x,x,x+30
`x=50^@`
`x+30=80^@`
∴ The required angles are `50^@,50^@, 80^@`
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