Advertisements
Advertisements
प्रश्न
Two angles of a triangle are equal and the third angle is greater than each of those angles
by 30°. Determine all the angles of the triangle.
Advertisements
उत्तर
Given that,
Two angles are equal and the third angle is greater than each of those angles `by 30^@` Let x, x, x+30 be the angles of a triangle
We know that
Sum of all angles of a triangle is `180^@`
`x+x+x+30=180^@`
`3x+30=180^@`
`3x=180^@-30^@`
`3x=150^@`
`x=150^@/3`
`x=50^@`
∴ The angles are x,x,x+30
`x=50^@`
`x+30=80^@`
∴ The required angles are `50^@,50^@, 80^@`
APPEARS IN
संबंधित प्रश्न
Can a triangle have All angles less than 60° Justify your answer in case.
In the given figure, AC ⊥ CE and ∠A : ∠B : ∠C = 3 : 2 : 1, find the value of ∠ECD.

State exterior angle theorem.
State, if the triangle is possible with the following angles :
125°, 40°, and 15°
In a triangle ABC, ∠A = 45° and ∠B = 75°, find ∠C.
In the given figure, express a in terms of b.

Classify the following triangle according to angle:

The length of the sides of the triangle is given. Say what types of triangles they are 3.4 cm, 3.4 cm, 5 cm.
The length of the three segments is given for constructing a triangle. Say whether a triangle with these sides can be drawn. Give the reason for your answer.
7 cm, 24 cm, 25 cm
D is any point on side AC of a ∆ABC with AB = AC. Show that CD < BD.
