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Question
The angles of a triangle are (x − 40)°, (x − 20)° and `(1/2x-10)^@.` find the value of x
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Solution
Given that
The angles of triangle are
`(x-40^@),(x-20)^@ and (x/2-10)^@`
We know that
Sum of all angles of traingle is `180^@`
∴ `x-40^@+x-20^@+x/2-10^@=180^@`
`2x+x/2-70^@=180^@`
`(5x)/2=180+70^@`
`5x=250^@(2)`
`x=50^@(2)`
`x=100^@`
∴ `x=100^@`
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